What would the solution pH be if all the sulphite were destroyed by the second reaction, and then all the acetic acid that remained was destroyed by the first reaction?

The condensate can be treated in an anaerobic biological treatment process, but only if the pH is maintained near neutrality (pH 7).

a. Find the pH of a solution of 5000 mg/L HAc and 300 mg/L H2SO3 as S . To do this generate a log C-pH diagram using Excel. Label all the lines and show on the diagram where the equilibrium pH is. You can use a charge balance to solve for pH.

b. What would the solution pH be if all the sulphite were destroyed by the second reaction, and then all the acetic acid that remained was destroyed by the first reaction? Again, do this by generating a log C-pH diagram with Excel . i.e. after rn 2: TOTSO3 = 0, TOTS = TOTSO3 initially TOTAc = initial –reacted TOTCO3 = that created from H2SO3 After rn 1: TOTAc =0 TOTS doesn’t change TOTCO3 = that from the 1st rn + that from 2nd rn Then set up problem and solve using log C-pH diagram

c. How much NaOH, in moles per litre, would be needed to bring the initial solution pH into the range of good reactability, say, pH 7.0? How much Na2CO3 would be required to accomplish the same result?

© 2020 Essaylane.com. All Rights Reserved. | Disclaimer: for assistance purposes only. These custom papers should be used with proper reference.